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Integrating a product: integration by parts. Suppose we want to integrate Xsin(X). We can integrate each of these functions separately, but how do we integrate the product of them? The answer is we use a technique called "integration by parts". First I'll tell you the formula, then show you how it works with that particular example, and then explain where on earth the formula came from! Here's the method. We have a product of two functions and we want to integrate this product. The first step is, we have to choose one of them to be integrated and one to be differentiated. (The result will be that the whole product gets integrated, but to get there we actually have to differentiate one of them. It seems strange but you'll see why later.) So we choose one to integrate and the other to differentiate. To remind us which one we're going to integrate we'll write it as the derivative of something, let's call it dv/dX, so when we integrate i

The following facts are only necessary for taking a decision between the two before mentioned  devices. *Also keep in mind the windows phone really does not need a dual core or quad core processor with huge amount of RAM to give a damn smooth performance like a much bloated android phones-So  don't let the hardware specs fool you when compared to specs of a android phone,Because This is "more than enough" for a windows phone to give smooth performance in a mind blowing  manner* Samsung Omnia W over Nokia Lumia 710: Super AMOLED Gorilla Glass display over TFT Slimmer profile and metal on the battery cover Lighter by 10g despite more premium finish Front-facing VGA camera Slightly better loudspeaker performance Better audio quality Nearly twice the real-world battery performance Standard SIM card support over MicroSIM Nokia Lumia 710 over Samsung Omnia W: Free lifetime Nokia Drive navigation Nokia Music and Nokia Maps Display is twice as bright Bette

CCNA is one among the most demanded network courses now days. The selection of such a course is really useful. So you go for CCNA. You can apply in job roles of Network Administrator, IT/Network manager, Network Engineer, and so on. Popular certifications in combination with the CCNA course are: - MCSE 2003 and CCNA - MCITP: Enterprise Administrator and CCNA - CCNA and CCNP "When asked by a person in a online forum about the chances of CCNA with  Btech -IT"

The degree of polymerization , or DP, is usually defined as the number of monomeric units in a macromolecule or polymer or oligomer molecule. [ 1 ] [ 2 ] [ 3 ] For a homopolymer, there is only one type of monomeric unit and the number-average degree of polymerization is given by For most industrial purposes, degrees of polymerization in the thousands or tens of thousands are desired. Some authors, however, define DP as the number of repeat units , where for copolymers the repeat unit may not be identical to the monomeric unit. [ 4 ] [ 5 ] For example, in nylon-6,6 , the repeat unit contains the two monomeric units —NH(CH 2 ) 6 NH— and —OC(CH 2 ) 4 CO—, so that a chain of 1000 monomeric units corresponds to 500 repeat units. The degree of polymerization or chain length is then 1000 by the first (IUPAC) definition, but 500 by the second. In polycondensation , in order to achieve a high degree of polymerization (and hence molecular weight), X n , a high fractional monom

Polarization Index is an indicator which gives an idea of the cleanliness of the windings. It is a ratio of the Insulation Resistance Measured for 10 minutes to the insulation resistance value measured after 1 minute. Since it is a ratio; it does not have any units. Polarization Ratio = Insulation Resistance after 10 minutes/ Insulation Resistance after 1 minute The Polarization Index should be above 2.0 to be permissible. Machines having PI below 2.0 cannot be operated. The Polarization Index does not have any significant relation with temperature upto 50 deg. C. However, the Polarization Index test should not be conducted at a temperature beyond 50 deg. C